Let’s get back to the basics…
Suppose the Volt has the following numbers:
Gross weight: 1800kgs (3960lbs)
Rolling resistance coefficient: 0.015
Cd: 0.25
Frontal area: 1.6m*m
Air density: 1.247
Gravity: 9.81
In order for this car to go 70miles/h (31meters/s) it will need the following amount of HP:
HP needed to roll: 0.015*9.81*31*1800/750 = 10.94796
HP need to sustain 70mph against wid: 0.5*0.25*1.6*1.247*31*31*31/750 = 9.9065
HP lost or consumed internally (electrical+mechanical+HVAC+lights) = 10 approx.
Altogether the Volt needs about 31HP to run at 70mph on a flat smooth road, which is well within the max output of the ICE.
Now, suppose you want to pass an 18-wheeler in front of you by increasing speed to 85miles/h (38meters/s) in 10 seconds…
Motion energy at 70mph: 0.5*1800*31*31 = 864900
Motion energy at 85mph: 0.5*1800*38*38 = 1299600
Therefore, you need an extra 434700 joule of energy to pass the 18-wheeler. If this job is to be done in 10 seconds you need 43470 joule or 57.96HP every second in addition to the abovementioned 31HP making the total requirement to about 89HP. This is beyond the capability of the ICE, therefore, you must tap into the reserve energy in the battery. I do not think you can do this passing so often once you start putting your hand in the battery. If the road is uphill, do not attempt to pass.
Note: The above requirement of 89HP does not include increase in rolling resistance and wind resistance at 85mph, which should require about 20HP more than at 70mph.